Time Zone

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)

Total Submission(s): 495    Accepted Submission(s): 162

Problem Description

Chiaki often participates in international competitive programming contests. The time zone becomes a big problem.

Given a time in Beijing time (UTC +8), Chiaki would like to know the time in another time zone 

s.

 

 

Input

There are multiple test cases. The first line of input contains an integer 

T (1≤T≤106), indicating the number of test cases. For each test case:

The first line contains two integers a, b (0≤a≤23,0≤b≤59) and a string s in the format of "UTC+X'', "UTC-X'', "UTC+X.Y'', or "UTC-X.Y'' (0≤X,X.Y≤14,0≤Y≤9).

 

 

Output

For each test, output the time in the format of 

hh:mm (24-hour clock).

 

 

Sample Input

3 11 11 UTC+8 11 12 UTC+9 11 23 UTC+0

 

 

Sample Output

11:11 12:12 03:23

 

 

Source

 

 

题意：北京标准时间是UTC+8

现在给出标准的北京时间和别的地方的时区

要求别的地方的当前时间

模拟题：

注意细节：1 会有浮点误差，所以把小数位拿出来单独计算

　　　　　2注意当h小于0的时候，要转换成前一天的时间

　　　　　3是UTC-xy时，可以当成是当前时间+16-xy的时间

代码如下

#include 
       
        #include 
        
         #include 
         
          #include 
          
           using namespace std;int main(){  int T;  scanf("%d",&T); while(T--){    int hh,mm;    scanf("%d%d",&hh,&mm);    char str[100];    scanf("%s",str);    int len=strlen(str);    int flag=0;    int th=0;    int tm=0;    if(str[3]=='+'){      for(int i=4;i
           
            =60){          mm-=60;          th++;        }      }      hh+=(th-8);      if(hh>=24) hh-=24;      if(hh<0) hh+=24;      if(hh<10) cout<<"0"; //前导零      cout<
            
             <<":"; if(mm<10) cout<<"0"; cout<
             
              <
              
               =24) hh-=24; if(hh<10) printf("0"); printf("%d:",hh); if(mm<10) printf("0"); printf("%d\n",mm); } } return 0;}/*01 14 UTC+2.619:50*/